Question

1.- The position of a body in one-dimensional movement as a function of time is represented in the figure.
a) Where the movement is in the positive or negative direction of the x's
b) When the movement is accelerated or delayed
(c) When the speed is zero
d) Approximate value of speed up to t= 0.8s
e) When the acceleration is different from zero

X(m) 1 - - - 0'1 2,0

Answer 1

Body movement is in positive x-direction as x-t graph moves along +ve x-axis with time. Movement will never be accelerated as slope of the x-t graph either constant or zero with respect to time axis. dv d²x d ( dx dt dt dt dt Speed will be zero when position of x does not change with respect to time t. Therefore, for period t=0.8 sec to t=1.8 sec, speed is zero. Calculate the speed upto t=0.8 sec. v== slope of the curve = X-X1 dt t2 - 41 0.55-(-0.3) =1.0625 m/s 0.8-0 All the curves either sloped straight line or zero slope straight line. It means velocity will either be constant or be zero. It means acceleration will always be zero.