Question

.- The position of a body in one-dimensional movement as a function of time is represented in the figure. a) Where the movement is in the positive or negative direction of the x's b) When the movement is accelerated or delayed (c) When the speed is zero d) Approximate value of speed up to t= 0.8s e) When the acceleration is different from zero

X(m) 1 - - - 0'1 2,0

Answer 1

solution Q-2,7) 7 (0.815.5) 5 M 3 26,0 2 - 2 constant. Diese (se) sec 110,-37 (2.8, -2) a oxta og sec for this time interval (10,5.5) movement is in tivex direction but speed is 0.3<t<0.8 movement is in tire x- deredion. foro.et ds 1.8 sec body is staionary at x = 5.5mt for 1-84 t < 2.2 sec body movement is in time x-dinechon for 9.224(2.8 movement is in page sec negative ne X - body direction. to zero for t > 2-8 sec body movement is in positive x-dire don b) at t = 0.8 see speed goes zero so at t = 0.8 sec body speed is delayed or brake applied. body speed again so body is accelerated increases at t= 1.8 see

80 body is at t= 2.2 sec body mom movement changes from time to neg ative x-direction so retarded (delayed) at t = a8 bec body movement goss -ine to time so body ń accelerated speed is zero in the internal 0.8T AC 1.8 see speed up to 0.8sec 5.5-(-3) speed tj - tin speed = 10.625 m/sec es at t=0.8 sec, 1.8 sec, 2.2 sec and 28 sec body movement changes ie speed changes so acch at this time is different from q 8-5 St - Sin 8 Mig 0.8 85 zero