Question

A sphere of radius R can rotate about a vertical axis on frictionless bearings (see figure below). Let the rotational inertiaVo = 0, m = 3.0 kg, h = 1.0 m. Mass of sphere: Msphere = 5.5 kg, radius of sphere R = 0.20 m Mass of pulley: Mulley = 1.5

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Answer #1

AnA.) radius of sphere R radius of Pulley = e at t=0 speed of mass mev. = Ei= - (a) initial energy of the system 14 mv ² t /

final energy Ef Es ( m+ & Isphere it I pulley & J V Vf final speed of mass m . Contenvation of energy gives Ei Et m+ t Ispher

case 1 2 72 Sphere is solid = Ispires = = ? MB 5 Pulley is a solid disk of radius i = Int 2 hence Uf = amgh m + 2 misphen R²

2 case Sphere is thin spherical shell = Espinne 2/3 Mspree R² Pulley is a solid disk of radius i - I pulley = 1/2 Mpulley i V

V = mt 2 li Ipulley - Ź Mouttert Rit) this time we becomes. [ 2mgh 1/2 23 Msphere + / Moulley (Rita) Ri 2x3 x4.8 X1 V2 3 + 2/

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