Question

mystery (numi, num2) ? public static void main(String[] args) int numl = 7; int num2 = 13; int result = mystery (numi, num2); } public static int mystery (int firstNum, int secondNum) { firstNum = firstnym * 3; secondNum = secondnum * 2; return firstNum + secondNum; } numl: A num2: A

Answer 1

Given code:

public static void main(String[] args)
   {
   int num1=7;
   int num2=13;
   int result=mystery(num1,num2);

   }
   public static int mystery(int firstNum,int secondNum)
   {
   firstNum=firstNum*3;
   secondNum=secondNum*2;
   return firstNum+secondNum;
   }

ANSWER:

num1 = 7

num2 = 13

result = 47

EXPLANATION: initially num1 and num2 are initilized with some values.

and these two values are passing to the function mystery()

and perform operations on these values:

firstNum=firstNum*3;
   secondNum=secondNum*2;
   return firstNum+secondNum;

and return the result

I EXECUTE THE ABOVE CODE WITH ADDING SOME PRINT STATEMENTS.

CODE:

public class Main
{
   public static void main(String[] args)
   {
   int num1=7;
   int num2=13;
   System.out.println("The num1: "+num1);
       System.out.println("The num2: "+num2);
   int result=mystery(num1,num2);
       System.out.println("The result: "+result);
      
   }
   public static int mystery(int firstNum,int secondNum)
   {
   firstNum=firstNum*3;
   secondNum=secondNum*2;
   return firstNum+secondNum;
   }
}

OUTPUT:

The numl: 7 The num2: 13 The result: 47 ... Program finished with exit code 0 Press ENTER to exit console..

SCREENSHOT OF THE CODE:

4- Main.java 1 public class Main 2 { 3 public static void main(String[] args) { 5 int num1=7; 6 int num2=13; 7 System.out.println("The num1: "+num1); 8 System.out.println("The num2: "+num2); 9 int result=mystery (num1, num2); 10 System.out.println("The result: "+result); 11 12 13 public static int mystery(int firstNum, int secondNum) 14 - { 15 firstNum=firstNum*3; 16 second Num=secondNum*2; 17 return firstNum+secondNum; 18 } 19} } 20