Answer:
claim is P 0.354
a)
This is two tailed test.
b)
test statistics: z= 1.92
p-value = 2 * ( 1- p( z < 1.92 ))
using normal z table we get,
p(z< 1.92) = 0.9726
p-value = 2 * ( 1 - 0.9726 )
p-value = 0.0548
P-Value = 0.055
c)
decision rule is
Reject Ho if ( p-value ) <
here (p-value = 0.055 ) > 0.01
hence,
D.fail to reject Ho, There is not sufficient evidence to support the claim that p 0.354
The test statistic of z = 1.92 is obtained when testing the claim that p+0.354. a....
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