Question

The composite plate of uniform thickness is fabricated from two metals. The metal in volume A has a mass density of 8.00 Mg/mº and the metal in volume B has a mass density of 9.00 Mg/m? a) Determine the total mass of the composite plate. b) Determine the location of the mass center G referenced from the origin of the coordinate system. А 225 mm 150 mm B 150 mm 30 mm

Answer 1

Total mass = volume of AXSA + volume of B y le M = { x (300 +150) X 225 X 30 X 10^9 x 8 +3X150X225x 30 x 10-9 x 9 M = 0.0167 mg Auswer mass.of. A = { x(300+150) X 225 X30X10-9 xd MA=0.01215 ng MB= M-MA = 0.0167-0101215 N s IT = 0.00455 mg mi = mass of PSR= MA = 0.0040 mg za m2= mass of SRUT =ŽMA= 0.0081 mg m3 = mass of P Q R = MB = 0.00455 mg P. mass centre of PSR=(34.7)ares) = (200,150) mass centre of SRUT = (x2L2) =(75,11205) mass centre of PQR=(23;Z) CS = (250,75) CamScanner R 2150 4150 - Figi - Front view of composite plate Scanned with

mass centre xa = mize + m2 22 +383 mit met my 0.00405 x 200+ 0.0081X75+ Oro0455 X 250 0.00405 +0.0081 +0.00455 xa = 153 mm mass centre Ya -30 =-15 mm 2 mass centre Zaz Ezemtazamt blu mitmatwa 00405 X 150 +.0081X112.5+ .00455x75 .004051.0081+.oouss = 108.14 mm so mass centre a = (sea, yq, za ) =(153,-15, 108-14) 108-14) mm Answer Scanned with Cam Scanner