Question

4. (4.29/5 Points] DETAILS PREVIOUS ANSWERS DEVORESTAT9 9.E.024. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Damage to grapes from bird predation is a serious problem for grape growers. An article reported on an experiment involving a bird-feeder table, time-lapse video, and artificial foods. Information was collected for two different bird species at both the experimental location and at a natural vineyard setting. Consider the following data on time (sec) spent on a single visit to the location. (Note: Assume the populations are normally distributed.) x Species Blackbirds Blackbirds Silvereyes Silvereyes Location Expti Natural Expt! Natural 40 30 33 27 13.9 9.8 49.5 38.1 SE mean 2.03 1.75 4.75 5.07 (a) Calculate an upper confidence bound for the true average time that blackbirds spend on a single visit at the experimental location. (Use a = 0.05. Round your answer to two decimal places.) 17.88 X sec

(a) 17.88 sec is wrong.

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Answer 1

Blackbird species, Experimental location,

n=40, xbar= 13.9 , SE(mean)= sigma/√n= 2.03

Upper bound for blackbird species of experimental location is, 17.2391

1. In Excel, click Data Analysison the Data tab.
2. From the Data Analysis popup, choose F-Test Two-Sample for Variances.
3. Under Input, select the ranges for both Variable 1 Range and Variable 2 Range.
4. Check the Labels checkbox if you have meaningful variables labels in row 1. This option helps make the output easier to interpret. Ensure that you include the label row in step #3.
5. Excel uses the default Alpha value of 0.05, which you usually won’t need to change. Alpha is also known as the significance level.
6. Click OK.

For our results, we’ll use the P(F<=f) one-tail row, which is the p-value for the one-tailed form of the variances test. Because our p-value (0.00649) is less than the standard significance level of 0.05, we can reject the null hypothesis. Our sample data support the hypothesis that the population variances are different.

J7 G A a) 1 2 n= H Calculate an upper confidence bound for the true average time for blackbird species at experimental location. 40 mean= 13.9 SE(mean) 2.03 Upper bound=mean+z(0.95) *SE(mean) z(a=0.05) 1.64485 UB= 17.2391 sec. 3 4 5 6 7 2) Brand A 8.55 8 9 10 8.84 8.91 8.82 11 Brand B F-Test Two-Sample for Variances 8.66 Set relevent hypothesis as, 8.71 Brand A Brand B Ho:01? = 022 Vs Ha: 01? + 022 8.81 Mean 8.76111 8.70889 8.7 Variance 0.01529 0.00221 The output indicates that variance for brand A is 8.7611 & 8.73 Observations 9 9 variance for brand B is 0.0022111 8.66 df 8 8 8.68 F 6.91332 8.74 P(F<=f) one-tail 0.00649 8.69 F Critical one-tail 3.4381 12 13 14 8.85 8.62 8.72 8.68 8.86 15 16 Wilcox Sheet3 testing mean sample size CI test_treat_placebo Sheet4 KLUB Ready Type here to search