Question

Four groups of college students underwent a sleep deprivation study. There were 6 participants per condition. They had been deprived of sleep for 0, 6, 12, or 24 hours. Afterwards, a memory test was given. An ANOVA was conducted in Microsoft Excel and the results are given in the table below. Follow-up this ANOVA with a post hoc test (α= .01) to determine which groups differed. Construct a table of mean differences to organize the means. Make certain to explain the results.

SUMMARY Groups 0 hr 6 hr 12 hr 24 hr 11 6 6 6 6 Sum 51 45 26 19 ANOVA Source of Variation SS Between Treatments 115.458 Within Treatments 31.167 Total 146.625 F 24.697 P-value 0.000 F crit 4.938 df 3 20 23

Answer 1

Comparison	Mean 1	Mean 2	N1	N2
1: 1	+ 8.5	+ 7.5	6	6
2: 2	+ 8.5	+ 4.3	6	6
3: 3	+ 8.5	+ 3.2	6	6
4: 4	+ 7.5	+ 4.3	6	6
5: 5	+ 7.5	+ 3.2	6	6
6: 6	+ 4.3	+ 3.2	6	6

1:1 is 0hr vs 6 hr

2:2 is 0 hr vs 12 hr

3:3 is 0hr vs 24hr

4:4 is 6 hr vs 12 hr

5:5 is 6 hr vs 12 hr

6:6 is 12 hr vs 24 hr

Comparison	Mean1 - Mean2	95% CI of difference
1: 1	+ 1.0	- 1.1 to + 3.1
2: 2	+ 4.2	+ 2.1 to + 6.3
3: 3	+ 5.3	+ 3.2 to + 7.4
4: 4	+ 3.2	+ 1.1 to + 5.3
5: 5	+ 4.3	+ 2.2 to + 6.4
6: 6	+ 1.1	- 1.0 to + 3.2

Statistical Significance

Comparison	Significant? (P <0.05?)	t
1: 1	No	1.388
2: 2	Yes	5.828
3: 3	Yes	7.354
4: 4	Yes	4.440
5: 5	Yes	5.967
6: 6	No	1.526

Mean Square= 1.558    DF= 20

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