Question

If the angle θ=θ= 30 ∘∘ , determine the acceleration of the truck. The coefficient of kinetic friction between the pipe and the ground is μk=0.20μk=0.20.

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Answer #1

T mg 14 T 0.4 m 0.4 m ma q 0.2N IN

Taking moment about G;

\sum M_G = 0

\Rightarrow Tsin(45^o-30^o)(0.4) - 0.2N(0.4) = 0

\Rightarrow N = 1.2941T

Equilibrium of forces;

\sum F_y = 0

\Rightarrow N - 870(9.81)+Tsin45^o = 0

\Rightarrow 1.2941T - 870(9.81)+Tsin45^o = 0

\Rightarrow T = 4264.787\;\;N

and

\sum F_x = ma

\Rightarrow Tcos45^o - 0.2N = 870 a

\Rightarrow Tcos45^o - 0.2(1.2941T) = 870 a

\Rightarrow (4264.787)cos45^o - 0.2(1.2941\times4264.787) = 870 a

\Rightarrow a = 2.20\;\;m/s^2

Answer:

a = 2.20\;\;m/s^2

T = 4265\;\;N

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