Question

Consider the simply supported beam shown in the figure below. Let x be the distance measured from left end of the beam. 1. Determine the vertical reactions at A and C 2. Write the equations for shear and moment for the section of the member between B and C. 3. Draw the shear and moment diagrams for the entire beam, specifying values at changes in loading and locations where the shear is 0. 48 KN B kN/m D internal pin (Moment release)

Answer 1

RKNIM 40KN 1A .000 D 4 m B K 4m-*2m - At point 8 , Internal Hinge, where BM = 0 bor fig 2) - : EMC =0 FB.D. 48x2= R1 X 4 fotobooth KNIT Ri= 24 KN A B 48UN С. -4m RA R 4m RA am- figo Rei Rit Rc = 48 Hyos Re = 24UN A 32 KN 18. RI RA foo figcis :- RA= 32+ R- 32+024 = 56YN RA = 56kN 1 lo & RA = 569 N and Rc=24KN Sheer Equation between B and C (SF)xx -R,=24 KM (B.M) x-x = Ria=24R 3. Between Point A to B. X 1007UT (SF) x-x Rq - 8x=24tax (BM)x.x RA Rix +Qx? Sheen force Diagram :- (BM)A =24x414x42 = 160 WN-m. non =24x +42? Kat X 56 KN 24 48 KN A C Bending moment Diagram :- A 160 kvm 96 km B C D Sheur force is Loro at point 'D'.