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Consider the simply supported beam shown in the figure below. Let x be the distance measured from left end of the beam. 1. De
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Solution: 148kN. 8kW/m 24Kw.ro Ay 4m 3m 3mo EMFO > 48(10) - Cy(3) - 864)() +24 = 0. 480 - 3cy – 64 +24 50 acy = 440 = (y = 6Bm = - 46.857 n +32(2-2) 0.- - 14-8577-64 +24 for the Spar -- CD (2. from a Span SF = Ay + + 8 (4) + Cy Bm- 24 + 4y®+ 8(/2-42

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