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The mean annual income for people in a certain city in thousands of dollars) is 39...
Annual income: The mean annual income for people in a certain city in thousands of dollars) is 41, with a standard deviation of 35. A pollster draws a sample of 91 people to interview. Part 1 of 5 (a) What is the probability that the sample mean income is less than 37? Round the answer to at least four decimal places. The probability that the sample mean income is less than 37 is Part 2 of 5 (b) What is...
Queston 9 of 10 (1 point) View problem in a pop-UR Annual income: The mean annual income for people in a certain city (in thousands of dollars) is 43, with a standard deviation of 23. A pollster draws a sample of 91 people to interview. 6 2 Section Exercise 29 (calc) Part 1 out of 5 What is the probability that the sample mean income is less than 40? Round the answer to four decimal places. The probability that the...
The mean salary of people living in a certain city is $37500 with a standard deviation of $1589. A sample of 46 people is selected at random from those living in the city. Find the probability that the mean income of the sample is less than $38000.
An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in California. Suppose that the mean income is found to be $24.3$24.3 for a random sample of 758758 people. Assume the population standard deviation is known to be $9.2$9.2. Construct the 90%90% confidence interval for the mean per capita income in thousands of dollars. Round your answers to one decimal place.
An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Californ Suppose that the mean income is found to be $21.3 for a random sample of 2817 people. Assume the populatio standard deviation is known to be $79. Construct the 98 % confidence interval for the mean per capita income i thousands of dollars. Round your answers to one decimal place. Keypad 1 Point Answer(How to Enter) Lower endpoint Upper endpoint:
An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. Suppose that the mean income is found to be $23.4 for a random sample of 211 people. Assume the population standard deviation is known to be $5.7. Construct the 80 % confidence interval for the mean per capita income in thousands of dollars. Round your answers to one decimal place. Keypad Tables Points AnswerHow to Enser) 2 Lower endpoint□ーーコ Upper...
The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,041. A sample of 63 people is selected at random from those living in the city. Find the probability that the mean income of the sample is within $500 of the population mean. Round your answer to 4 decimal places.
9) The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.
Scaling Data Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 50
Solve the problem. Annual precipitation in a certain city is normally distributed with a mean of 99 inches, and a standard deviation of 18 in. Find the probability that the mean annual precipitation during 35 randomly picked years will be less than 101.8 in.? Group of answer choices 0.8212 0.3212 0.9203 0.6788 0.1788