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Question 22 (4 points) Cr2O72- + 3 H2O2 + 8 H+ + 2 Cr3+ + 3 O2 + 7 H2O In the above reaction Ocrin Cr₂O7 2- is reduced. OH in
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Answer #1

2 - Cr₂O4 + 3H₂O2 + 3H2O2 + 8H+ ->2634+ 30, + 7H,0 transfered to in this Reaction electrons are H₂ to Gr202 So Cr2O7 is the o

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