Question

(IV) The densities of gold, mercury, magnesium, and bromine are quoted below. Bromine and mercury are liquids (at room temperature), while gold and magnesium are solids. Substance Gold Mercury Magnesium Bromine Density (kg/m) 19,300 13,500 1,750 3,100 (a) A small gold nugget is dropped into a large sample of bromine. The gold nugget (CHOOSE ONE: (s) sinks to the bottom of the container holding the bromine. (n) floats completely immersed in bromine. (f) floats with a portion of its volume above the surface of the bromine. (b) If your answer for (a) is (s), then compute the fraction by which its apparent weight (submerged) differs from its normal weight (as measured in a vacuum, or air). If your answer for (a) is (n), compute the depth, below the surface, at which the gold sample floats. If your answer for (a) is (), compute the fraction of the gold sample which floats above the bromine. (c) A small magnesium ingot is dropped into a large sample of mercury. The magnesium ingot (CHOOSE ONE: sinks to the bottom of the container holding the mercury. floats completely immersed in mercury. (f) floats with a portion of its volume above the surface of the mercury. (d) If your answer for (c) is (s), then compute the fraction by which its apparent weight (submerged) differs from its normal weight (as measured in a vacuum, or air). If your answer for (c) is (n), compute the depth, below the surface, at which the magnesium sample floats. If your answer for (c) is (t), compute the fraction of the magnesium sample which lies above the mercury.

Answer 1

a Bromira (Co= 3100) ③ Sink to the bottom of the contains Let volume of nuget =V Solution -gold (h=19300) holling the bromire. bucawa high devity of gold due to this rink in container. [esight of nugget = [appert wight = zvg - GVy] (Sg - So)vg Fraction of apparent weight = vova] (maisen vacum) - Apparuit cuight wright inain W2( س ) Va So pg =)- 3100 19300 - 0.84 tadion of apprast cought = 0.84 part of weight in ana vaccum.

Sug=1750 Because the density of magnussium is low > Heads with a portionof its volume abou the surface boundary. Sty=13500 as compared to density of mencuny. Sing = 1750 =13500 t Sty=135 Let us consider the volume of nugget=V wright of nugget = Smg Vg boyancy force by prescury = My Vig v=displace volume Smyva = Pryvly v' =vx Img PHO 1750 = VX 735oo V = 0.130v) So that only 0.13v part of samples which below the surface of mucury So that Vatabore erunfuce =v-vi = V-0.1301 Vatereface = 0.87V Only this part of sample about the mercury sughe