Question

QUESTION 19

1. In glycolysis, fructose 1,6-bisphosphate is converted to two products with a ∆G'° of 23.8 kJ/mol. Under what conditions encountered in a normal cell will the free-energy change (∆G) be negative, enabling the reaction to proceed spontaneously to the right?

   	A.	Under standard conditions, energy is released to drive the reaction to the right,
   	B.	the reaction will not go to the right spontaneously under any conditions because the ∆G'° is positive,
   	C.	the reaction will proceed spontaneously to the right if there is a high concentration of products relative to the concentration of fructose 1,6-bisphosphate,
   	D.	the reaction will proceed spontaneously to the right if there is a high concentration of fructose 1,6-bisphosphate relative to the concentration of products, none of the above conditions is sufficient.
   	E.	all of the above conditions are sufficient.
   	F.	none of the above conditions is sufficient.

Answer 1

The correct option is  

D.	the reaction will proceed spontaneously to the right if there is a high concentration of fructose 1,6-bisphosphate relative to the concentration of products.

When ΔG is negative, a process will proceed forward spontaneously and will be exergonic and when ΔG is positive, the process is endergonic and spontaneous in the reverse direction. Any change in the initial concentrations of the reactants or products will affect ΔG. High concentration of reactant molecules or low concentration of product molecules can favor a chemical reaction in the direction of products.