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A cross-section is subjected to a maximum shear of V=220 kN (see figure): 1. Determine the centroid of the cross-section. 2.
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250 10 y centroid :- {(300x10JX 1504x2 +@soxib)x305 + (125x10 bess+(128gxas (300x10)^{2}+ @soxid) +(asxto)+(3810) 100 ý = 10Up Vote the Answer. Thank you ?... Stay Safe

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