Question

o a Suppose the lengths of human pregnancies are normally distributed with p = 266 days and 6 = 16 days. Complete parts (a) a
o Assume the random variable X is normally distributed with mean u = 50 and standard deviation 6 = 7. Compute the probability
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Answer #1

(a)

The first interpretation of the picture is,

B. The proportion of human pregnancies that last more than 300 days is 0.0168

The second interpretation of the picture is,

A. The probability that a randomly selected human pregnancy lasts more than 300 days is 0.0168

(b)

The first interpretation of the picture is,

A. The proportion of human pregnancies that last between 200 and 300 days is 0.9710

The second interpretation of the picture is,

B. The probability that a randomly selected human pregnancy lasts between 200 and 300 days is 0.9710

The normal curve C. corresponds to P(34 < X < 61)

P(34 < X < 61) = P(X < 61) - P(X < 34)

= P[Z < (61 - 50)/7] - P[Z < (34 - 50)/7]

= P[Z < 1.57] - P[Z < -2.29]

= 0.9418 - 0.0110

= 0.9308

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