The organisms can be easily differentiated in the basis of (+) and (-) notation which suggest the wild type progeny and wild type respectively. There are twenty mutated and thirty-six wildtype gene, Since the symbols of mutation in mutant 2 and mutant 6 is same so there are highly likely to have similar mutation.
In the mutant 2, mutation is occurring mut-2, mut-4, mut-5 and mut-9, wherein mutation in mutant 6 are at mut-2, mut-4, mut-5 and while compare altogether, mut-2 is in all cases of mutant 2 and also in mutant 6.
Based on the data from this complementation analysis, how many different genes appear to be mutated?...
A complementation test was conducted with 7 different mutant organisms (numbered 1-7), all having the same mutant phenotype. All 7 mutants were crossed to each other and the results are below. Using the chart of the complementation test, answer the following questions. (6 points) 1 2 3 4 5 6 7 1 - + + - - + + 2 + - + + + + - 3 + + - + + + + 4 - + + -...
Question 9 In an analysis of other rII mutants, complementation testing yielded the following results: Mutants Results (+/- lysis) 1,2 -- 1,3 -- 1,4 + 1,5 + Which mutants are in the same complementation group as mutation #1? a. mutant 2 b. mutant 3 c. mutant 4 d. mutant 5 e. None of these mutations are in the same complementation group. f. All of these mutations are in the same complementation group.
Eight mutant bacteriophage strains cannot lyse a certain type of bacteria that can be lysed by wild-type bacteriophages. The mutant strains were allowed to infect the bacteria in a complementation test. A "+" indicates that lysis occurred with coinfection. A "-" indicates that lysis did not occur. 1 2 3 4 5 6 7 8 1 - + + + + - + + 2 - + + - + - + 3 - - + + + - 4...
The same region of point mutations from problem 8 was analyzed for complementation by allowing the haploid lines to form diploid lines and testing the resulting phenotypes. The complementation test allows one to determine how many genes are represented by the mutant lines above. Determine the number of genes and place them on your map for problem 5.(6 points) Complementation Test Data crossed to
What mutants are in the same complementation group as M2? Select as many as apply. Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
フ③Using he complementation grid above, how many genes are responsible or the 6 mutants used in the cross? b. 3 d. 5 フ③Using he complementation grid above, how many genes are responsible or the 6 mutants used in the cross? b. 3 d. 5
What mutants are in the same complementation group as M4? Select as many as apply. Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
1, How many genes are present? 2, What are the complementation group? (The missing part is all negative-) Question Completion Status: QUESTION 51 A complementation test was performed on eight mutant soy-bean plants. The results are as follows A - B + C - D - E + F + G + H + + + + + + + + + + + + Click Save and Submit to save and submit. Click Save All Answers to save all...
2) Eight different point mutations are studied by complementation test and by der mapping. The results of all pair-wise complementation tests between shown below. A) Classify these eight mutants into genes. 1 2 3 4 B) The eight point mutations are crossed with three deletion mutants. Taking these and the complementation data into account, indicate the order of mutations 1-8. Draw circles around paired mutations in the same gene. Also draw three lines beneath the map to indicate the position...
Help needed on complementation testing of yeast. Eight uncoordinated mutants are recovered in a mutagenesis screen. A complementation test is carried out and the results are displayed below. You also determine that unc-2 in your screen is an allele of a previously described mutant, unc-247. Which other mutants recovered in this screen are most likely also alleles of unc-247? unc-unc-unc-uncunc-unc-uncUnc- 8 unc- unc- UNC WT WT WT UNC UNC unc- unc- UNC | WT | WT |WT unc- UNC WT...