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フ③Using he complementation grid above, how many genes are responsible or the 6 mutants used in the cross? b. 3 d. 5 フ③Using he complementation grid above, how many genes are responsible or...
14..........In Neurospora (a fungus), a complementation test was performed on tive haploid mutants Wild-type in appearance,...
14..........In Neurospora (a fungus), a complementation test was performed on tive haploid mutants Wild-type in appearance, and means showed abnormal branching. (3 pts) It the table below, complementation crosses were made to establish which mutants rescue the mutation. A complementation group will contain mutants that can rescue the defective phenotype. OWN These results indicate that the mutations were in A) 1 gene. B) 2 genes. C) 3 genes. D) 4 genes. The polarity of DNA synthesis is: E) 5 genes....
What mutants are in the same complementation group as M4? Select as many as apply. Question...
What mutants are in the same complementation group as
M4? Select as many as apply.
Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
What mutants are in the same complementation group as M2? Select as many as apply. Question...
What mutants are in the same complementation group as
M2? Select as many as apply.
Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
A complementation test was conducted with 7 different mutant organisms (numbered 1-7), all having the same...
A complementation test was conducted with 7 different mutant organisms (numbered 1-7), all having the same mutant phenotype. All 7 mutants were crossed to each other and the results are below. Using the chart of the complementation test, answer the following questions. (6 points) 1 2 3 4 5 6 7 1 - + + - - + + 2 + - + + + + - 3 + + - + + + + 4 - + + -...
Based on the data from this complementation analysis, how many different genes appear to be mutated?...
Based on the data from this complementation analysis, how many different genes appear to be mutated? Also, do mutant 2 and mutant 6 necessarily have the same mutation? Explain. 1 + N 3 + 5 + + + - lu an 6 + 7 + + 8 9 + 10 + + + + + + + + + 1 2 3 4 5 6 7 8 9 10 Mutant
34. (6 points) Currently you are studying threonine synthesis in yeast. To find genes whose protein...
34. (6 points) Currently you are studying threonine synthesis in yeast. To find genes whose protein products are important for threonine synthesis, you perform a mutagenesis to find mutants that require a source of threonine to grow. You find a total of nine mutants, all of which have recessive phenotypes. You perform complementation tests with all of your mutants. Below are the results for your complementation tests. A (+) means growth and a() means no growth: mtl mt2mt3m4 mt mt...
1, How many genes are present? 2, What are the complementation group? (The missing part is...
1, How many genes are present?
2, What are the complementation group?
(The missing part is all negative-)
Question Completion Status: QUESTION 51 A complementation test was performed on eight mutant soy-bean plants. The results are as follows A - B + C - D - E + F + G + H + + + + + + + + + + + + Click Save and Submit to save and submit. Click Save All Answers to save all...
Help needed on complementation testing of yeast. Eight uncoordinated mutants are recovered in a mutagenesis screen....
Help needed on complementation testing of yeast.
Eight uncoordinated mutants are recovered in a mutagenesis screen. A complementation test is carried out and the results are displayed below. You also determine that unc-2 in your screen is an allele of a previously described mutant, unc-247. Which other mutants recovered in this screen are most likely also alleles of unc-247? unc-unc-unc-uncunc-unc-uncUnc- 8 unc- unc- UNC WT WT WT UNC UNC unc- unc- UNC | WT | WT |WT unc- UNC WT...
Bi2030 (12) Defining the gene 36 1210 A set of 10 deletion mutants of some unspecified...
Bi2030 (12) Defining the gene 36 1210 A set of 10 deletion mutants of some unspecified organism (#1-10) are tested for the production of 1 x2 4 x 10 ambiscity 2 x 7 5 x 8 wild-type recombinants when crossed pairwise to .2 x 10 5x9 12 7.1 O S one another. All tests are positive except those 3x6 5 x 10 shown on the night: 3x9 7 x 10 3 x 10 8x9 (a) Construct a map of these...
please help me!!! 5.) You have discovered mutants in two new gene mutants in Drosophila. One...
please help me!!!
5.) You have discovered mutants in two new gene mutants in Drosophila. One mutant, curl, has small, curly, nonfunctional wings. The other mutant, big, has enormous eyes. You decide to test if these two new genes are on chromosome #2, so you perform a three-gene linkage testcross using a gene that you know is on chromosome #2, trp, a mutant that cannot make its own tryptophan (and so must get it from its food). In all three...
14..........In Neurospora (a fungus), a complementation test was performed on tive haploid mutants Wild-type in appearance, and means showed abnormal branching. (3 pts) It the table below, complementation crosses were made to establish which mutants rescue the mutation. A complementation group will contain mutants that can rescue the defective phenotype. OWN These results indicate that the mutations were in A) 1 gene. B) 2 genes. C) 3 genes. D) 4 genes. The polarity of DNA synthesis is: E) 5 genes....
What mutants are in the same complementation group as
M4? Select as many as apply.
Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
What mutants are in the same complementation group as
M2? Select as many as apply.
Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
Based on the data from this complementation analysis, how many different genes appear to be mutated? Also, do mutant 2 and mutant 6 necessarily have the same mutation? Explain. 1 + N 3 + 5 + + + - lu an 6 + 7 + + 8 9 + 10 + + + + + + + + + 1 2 3 4 5 6 7 8 9 10 Mutant
34. (6 points) Currently you are studying threonine synthesis in yeast. To find genes whose protein products are important for threonine synthesis, you perform a mutagenesis to find mutants that require a source of threonine to grow. You find a total of nine mutants, all of which have recessive phenotypes. You perform complementation tests with all of your mutants. Below are the results for your complementation tests. A (+) means growth and a() means no growth: mtl mt2mt3m4 mt mt...
1, How many genes are present?
2, What are the complementation group?
(The missing part is all negative-)
Question Completion Status: QUESTION 51 A complementation test was performed on eight mutant soy-bean plants. The results are as follows A - B + C - D - E + F + G + H + + + + + + + + + + + + Click Save and Submit to save and submit. Click Save All Answers to save all...
Help needed on complementation testing of yeast.
Eight uncoordinated mutants are recovered in a mutagenesis screen. A complementation test is carried out and the results are displayed below. You also determine that unc-2 in your screen is an allele of a previously described mutant, unc-247. Which other mutants recovered in this screen are most likely also alleles of unc-247? unc-unc-unc-uncunc-unc-uncUnc- 8 unc- unc- UNC WT WT WT UNC UNC unc- unc- UNC | WT | WT |WT unc- UNC WT...
Bi2030 (12) Defining the gene 36 1210 A set of 10 deletion mutants of some unspecified organism (#1-10) are tested for the production of 1 x2 4 x 10 ambiscity 2 x 7 5 x 8 wild-type recombinants when crossed pairwise to .2 x 10 5x9 12 7.1 O S one another. All tests are positive except those 3x6 5 x 10 shown on the night: 3x9 7 x 10 3 x 10 8x9 (a) Construct a map of these...
please help me!!!
5.) You have discovered mutants in two new gene mutants in Drosophila. One mutant, curl, has small, curly, nonfunctional wings. The other mutant, big, has enormous eyes. You decide to test if these two new genes are on chromosome #2, so you perform a three-gene linkage testcross using a gene that you know is on chromosome #2, trp, a mutant that cannot make its own tryptophan (and so must get it from its food). In all three...
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