Question

2. Find the five-number summary and construct a boxplot for the following data: 12, 31, 23, 8, 23, 11, 33, 17, 28, 23, 23, 16 andro

Answer 1

Date solution i Given data 12, 31 23, 8.23,11, 33, 17, 21, 23, 23,16 1 Arrange the data in ascending order. 8,11,12, 16, 17, 23, 23, 23, 23, 28, 31, 33 o minimum value = 8 maximum value = 33. ( #')observation th 13 obs. 1. obs. (3.25) sbs + 0.25 (9th obs. - 3rd obs.) 3 12 + 0.25 (16-12) 13 th median 2 12th obs + ntz 2 obs:) 2 th ( 12 * $hs + obs. t 16 obs.) £ 123 + 23) median = 23.

Page No.: = + observation och trot th (9.75) observation 9th obs. t 0.7511th obs. 9th obs.) 12 23 + 0.75728-23) maad Q3 = 2675 Boaplot is given by. by cl ulov . + ru 15 20 25 30 35 44

Year (X)	Trucks (Y)	X^2	Y^2	XY
1984	15.9	3936256	252.81	31545.6
1985	16.3	3940225	265.69	32355.5
1986	16.8	3944196	282.24	33364.8
1987	17.2	3948169	295.84	34176.4
1988	17.5	3952144	306.25	34790
9930	83.7	19720990	1402.83	166232.3

Scatter plot 17.6 17.4 17.2 17 16.8 trucks 16.6 16.4 . 16.2 16 15.8 1983 1984 1985 1986 1987 1988 1989 year

3) F b We have EX 9930, EY - 83.7. EX=19720996 Ej? = 1402.83, EXy = 166232.3 NEXY - (EX) (EY) Vinzyl-(2x}]frey-8737 20.5 504 8.46 20. s 7423

Page NC 20.5 20.57 0.9967 Regression equation is, - at br. b = Say sax (EX)(ET) where, say EXT- A (9930) (837) 1662323 pe 2010 4.1 2 Saa Ex² (9930² 19720990 s jo b = 4.) 0.41

Now a = 7 - BY where, EJ 83. 16.75 EX 9930 1988 ( fel) 16.74 - 0.41 x 1986 L. - 797.52 Regression eg. is, ŷ 0.41% 797.52