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Check my work It is advertised that the average braking distance for a small car traveling at 70 miles per hour equals 120 fe

Find the p-value. 0.025 s p-value < 0.05 O 0.05 s p-value < 0.10 O p-value 20.10 O p-value < 0.01 O 0.01 s p-value < 0.025 pe

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Answer #1

(a)

Null hypothesis H0 : \mu = 120

Alternate Hypothesis H1: \mu \neq 120

(b)

We will be using the one sample t - test for this problem:

t = \frac{\overline{x} - \mu }{\frac{\sigma }{\sqrt{n}}}

where \overline{x} = sample mean = 111

\mu = hypothesized value of mean = 120

\sigma = population standard deviation = 21

n= sameple size = 35

t = \frac{111-120 }{\frac{21 }{\sqrt{35}}}

t = \frac{-9 }{\frac{21 }{5.9160}} = \frac{-9}{3.5497} = -2.5354

(b) The p value is 0.016014

Therefore, 0.01 < p value < 0.025 and the result is significant, so , we reject the null hypothesis.

(c) At 0.1 level of significane, the result is significant because 0.016014 < 0.1

Therefore, we reject the null hypothesis.

The average breaking distance is different from 120 feet.

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