Question

Find the dimensions of a rectangular box of maximum volume such that the sum of the lengths of its 12 edges is 66 ft. (x, y, z) =

Answer 1

let be rect anglun bon let be ac breadth box bon て be the sume of 12 is 66 length of erect angluan of g nectangular height of rectangular Give edges edges length of is equal to length rectangular bon, length length of 4 edges is of rectangular length of remaining edges length of height 4x + 4y + 4z out of 12 u edges of rec to breadth bou equals and 4 equals to 66 Z = ary 4 box is Volume of rectangular nyz using Vary) = xy(66 – 2-y) 4

y= て二 16G [m 12 2 (vy, z) = 5.5 , 5.5, 5-5) 。