Question

When 0.644 g of sodium metal is added to an excess of hydrochloric acid, 6690 J of heat are produced. What is the enthalpy of the reaction as written? 2 Na(s) + 2 HCl(aq) 2 NaCl(aq) + H,(8) kJ Enthalpy of reaction:

Answer 1

= Molar mass of na metal metal 23 g/mol .:. 0.6449 Na = 0.644 g 0.028 mole na 23 g/mol 2 Na (5) + 2 Helan) → znacl (aq) + (a) iie, 0.028 excess Hel is 6690J According to question enthalpy of the reaction of 0.644 64ag mole Na with enthalpy the given reaction where 2 mole Na reacts with Hel is 6690x2 J 0.028 447857.14 J 477.857 KT. This enthalpy of the reaction is of the reaction is 477.857 kJ.