Question

When 0.520 g of sodium metal is added to an excess of hydrochloric acid, 5410 J of heat are produced. What is the enthalpy of the reaction as written?

2Na(s) + 2HCl (aq) --(this dash is an arrow)-- 2NaCl (aq) + H2(g)

Enthalpy of reaction: kJ

Answer 1

let col be the heat produeced by 9X239 of Nede Na metade 0.520g of Na metal gives 540] of heat 2x939 of Na metal gives → W Cross multiply 0.5208 X=5410X 2 X 23 x= 478576.9230775 X= 478.576923077 KJ.