From the given information, the 95% confidance interval is (148.68411 and 162.4045),
that is lower limit is 148.68411 and upper limit is 162.4045.
To find the 95% error of margin (E), the formula is bellow,
The marginal Error is , E=
Hence 95% error of margin (E) = 6.86.
The option A is correct.
Use the following information to answer the following question. One sample T confidence interval: u: Mean...
Use the following information to answer the following question. One sample T confidence interval: u: Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.54433.473185440148.68411162.4045 What is the approximate typical size of the sampling error? A. 0.28 OB.3.47 OC. 155.54 OD. 6.86 E. unable to tell from the given output.
Use the following information to answer the following question One sample T confidence interval: : Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.54433.4731854 40 148.68411162.4045 How many beers were in the sample? OA. 41 OB. 12 OC.40 D.95 E unable to tell from the given output.
Use the t-distribution to find a confidence interval for a mean u given the relevant sample results. Give the best point estimate for u, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 95% confidence interval for u using the sample results I = 10.5,5 = 6.9, and n = 30 Round your answer for the point estimate to one decimal place, and your...
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Question Completion Status: One sample proportion summary confidence interval: P: Proportion of successes Method: Standard-Wald 95% confidence interval results: Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit р 68 285 0.23859649 0.025247422 0.18911245 0.28808053 a. Identify the 95% confidence interval for this given scenario. a. 18.9% < < 28.8% o b. 18.9% < < 28.8% 18.9% < X < 28.8% C 95% confidence interval results: Proportion Count Total Sample Prop. Std. Err. L. Limit...
In the picture below, I have the output for the same two sets of data. I ran the hypothesis test and the confidence interval. If you had a choice to use one output or the other, which would you choose and why? Make sure to be specific and include what information you get from each and what information you don't get if you use one over the other. Options Two sample T summary hypothesis test: : Mean of Population 1...
please check if correct and add a statement summarry of the
findings
4. Construct a 95% confidence interval for the average infant mortality rate. Be sure to write a statement summarizing your findings. One sample T confidence interval: Where: Group = "Infant" u : Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit 62.556325 1.5340462 331 59.538616 65.574035 Rate
33. Find the z-score used in the formula to construct a 92% confidence interval for a population proportion: O a. 1.4051 Ob. 1.5548 Oc. 1.7507 Od. 1.96 34. All of the following are TRUE about 95% confidence intervals for a population mean except ::* O a. The population mean may or may not be in the confidence interval. Ob. The value of T varies depending on sample size. Oc. If the sample size is large, the Central Limit Theorem says...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed x= 27, n=9, 0 = 6 a. Find a 95% confidence interval for the population mean The 95% confidence interval is from to (Round to two decimal places as needed.) b. Identify and interpret the margin of error. The margin of error is (Round to two decimal places as needed.) Interpret the margin of error. Choose the...