PLEASE ANSWER CLEARLY Question Completion Status: One sample proportion summary confidence interval: P: Proportion of successes...
PLEASE ANSWER CLEARLY The national figure for the percent of Americans on welfare is around 20%. In Lucas County, a random sample of 285 people found that 68 of them are on welfare. Suppose the claim the proportion of all people in Lucas County that are on welfare is greater than the national figure of 20%" is tested and resulted in not rejecting the null hypothesis. The 95% confidence interval is: One sample proportion summary confidence interval: P: Proportion of...
4. In a sample of 150 heads of households in the U.S.92 reported that they own their own home. Find a 99% confidence interval for the true proportion of the U.S. population that owns their own home The StatCrunch output for a 99% confidence interval is below. Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit р 92 150 0.61333333 0.039762256 0.51091255 0.71575412 a. Write out the interval and interpret the interval in the context of this problem....
Use the following information to answer the following question One sample T confidence interval: : Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.54433.4731854 40 148.68411162.4045 How many beers were in the sample? OA. 41 OB. 12 OC.40 D.95 E unable to tell from the given output.
Use the following information to answer the following question. One sample T confidence interval: u: Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.5443 3.4731854 40 148.68411162.4045 What is the 95% error margin for the variable Calories? A. 6.86 OB.13.72 O C.3.43 D.3.47 O E. unable to tell from the given output.
Use the following information to answer the following question. One sample T confidence interval: u: Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.54433.473185440148.68411162.4045 What is the approximate typical size of the sampling error? A. 0.28 OB.3.47 OC. 155.54 OD. 6.86 E. unable to tell from the given output.
In the picture below, I have the output for the same two sets of data. I ran the hypothesis test and the confidence interval. If you had a choice to use one output or the other, which would you choose and why? Make sure to be specific and include what information you get from each and what information you don't get if you use one over the other. Options Two sample T summary hypothesis test: : Mean of Population 1...
1.(10) Assume that the proportion of successes in a population is p. If simple random samples of size n are drawn from the population and the proportions, p. of successes in the samples are calculated, then the distribution of the sample proportions p is normal. What are the mean and standard deviation of this Normal distribution? Hp = 2.(10) How large do the number of successes and the number of failures in a sample have to be in order to...
I need help determining the decision for null hypothesis. For 1&2, set the type one error to 1% for 3-5, set the type one error to 5% Go to Statcrunch shared data sets and use the file Nutritional Data for Fast Food 2017. Set the type one error equal to 1% Complete the following: 1) Use STAT - proportions stats - one sample w data to test the hypothesis that the proportion of "burgers" made by Wendy's restaurants is less...
Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 155 with 20 successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. 95% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces Of 98 adults selected random from one town, 68 have health insurance Find a 90% confidence interval adults in he own who have heal e proportion on r e a ns rance 0585 < p < 0 802 B. 0.617<p<0.770 A. C. 0603 p<0.785 D. 0.574p<0.814 Use the given degree of confidence and sample data to...