Question

Use the following information to answer the following question One sample T confidence interval: : Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Calories in beer 12 oz 155.54433.4731854 40 148.68411162.4045 How many beers were in the sample? OA. 41 OB. 12 OC.40 D.95 E unable to tell from the given output.

Answer 1

Answer:- Since here we are using one sample T confidence interval. And we know that if we have sample mean xbar and sample standard deviation S then (1-${\alpha }$)% confidence interval by T distribution is

Xbar - t × S/(n)½ < T < xbar + t × S/(n)½

Where t is the critical value at (${\alpha }$/2) level of significance and (n-1) d.f.(degree of freedom) ,where n is sample size.

Here we have given d.f.= 40 i.e.,

n-1 = 40   => n = 41

So sample size is 41, hence 41 beers were in the sample.

Option (A) is correct.