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(a) Show that the function defined by the power series 20+1 y=(-1) 2n +1 n=0 satisfies the differential equation: (1+2?)y =

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Answer #1

y = 8 (-1. x2n+ 2n+1 no Now, (1+x²) y=1 dyt 1+22 da dy 1+x² Integrate both sides, we get y = S 1 + x x -6-1² an 완 Replaceof Now, the interval convergence -R< (2-3)<h » -1.2-3c1 2<x<34 (-u series t becomes, which is alternating series with an= ㅗ 7

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