For the reaction PC13(g) + Cl219) 5 PC15(g) at a particular temperature, Kc = 24.3. Suppose...
pe quests Consider the following reaction where Kc = 83.3 at 500K pl pl pt PC13(g) + Cl (8) =PC15(8) A reaction mixture was found to contain 4.62x102 moles of PC13(8), 4.49x10? moles of Cly() and 0.140 moles of PC13(e), in a 1.00 liter container Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? pl pt The reaction quotient, Qc quals pl pt The reaction A. must run in the forward direction...
Consider the following reaction where K. = 83.3 at 500 K: PC13(g) + Cl2(g) = PC15(8) A reaction mixture was found to contain 2.76x10-2 moles of PC13(g), 4.46x10-2 moles of Cl2(g) and 0.133 moles of PC13(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: (- 1. In order to reach equilibrium PC15(g) must be consumed. 2. In order to reach equilibrium K, must increase. 3. In order to reach equilibrium PC1z must...
Consider the following reaction where Kc = 1.20x10-2 at 500 K: PCl; (g)PCl3 (g) + Cl2 (g) A reaction mixture was found to contain 0.125 moles of PCls (2),4.99-102 moles of PCl3 (g), and 4.1 Indicate True (T) or False (F) for each of the follow ー▼ I. In order to reach equilibrium PC15(g) must be produced in a ▼ 2. In order to reach equilibrium Kc must decrease ▼ 3. In order to reach equilibrium PC13 must be consumed...
Given the following reactions, (1) 2PC13(g) = 2P(g) + 3Cl2(g) (2) PC13(g) + Cl2(g) =PC15(g) Kc = 0.0667 Kc = 4.0 calculate Kc for the reaction below. (3) 2P(g) + 5C12(g) = 2PC15(8) Ke=??? 23 240 Oo oo 1.1 60
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
Phosphorus pentachloride decomposes according to the chemical equation PC15(g) PC13(g) + Cl2 (g) Kc = 1.80 at 250° C A 0.475 mol sample of PCI, (g) is injected into an empty 4.90 L reaction vessel held at 250° C. Calculate the concentrations of PCI, (g) and PCI,(g) at equilibrium. [PCls] [PCl3]
The following reaction has an equilibrium constant, Kc, of 1.80 x 10-4 at a particular temperature: 2NOCl (g) → 2 NO (g) + Cl2 (g) You have a container in which the concentration of HOCl is 0.99 M, the concentration of NO is 0.45 M, and the concentration of Cl2 is 0.67 M. (a) Calculate the value of the reaction quotient Q. (b) Is the system at equilibrium? If not, predict which way (right or left) the reaction will proceed...
Consider the reaction. PC15(g) 근 PC13(g) + Cl2(g) K = 0.042 The concentrations of the products at equilibrium are PC, l = 0 10 M and [CI| = O. 1 3 M What is the concentration of the reactant, PCl, at equilibrium? PCI,I
For the reaction 2NH3(g)<->N2(g)+3H2(g), Kc=0.0076 at a particular temperature. If 0.025 M NH3, 0.50M N2, and 0.015 M H2 are mixed in a reaction vessel, is the reaction at equilibrium? If not, in what direction will the reaction shift to reach equilibrium?
The equilibrium constant, K, for the following reaction is 5.56×10 2 at 541 K. PC13(g) PC13(e) + Cly(8) An equilibrium mixture of the three gases in a 13.5 L container at 541 K contains 0.245 M PCI, 0.117 M PC13 and 0.117 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 6.44 L? M [PC15] = [PC13] = [CI] M...