Question

For a solution composition of 25.0 g solute and 100.0 g solvent; choose the correct numerical concentration of % (m/m). 20.0

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Answer #1

q)

mass of solute = 25 g

mass of solvent = 100 g

mass of solution = 125 g

So 25 g of solute present in 125 g of solution.

% m/m of solute is determined by calculating mass of solute in 100 g of solution.

125 g of solution contains 25 g of solute.

100 g of solution contains how much solute = ?

So mass of solute in 100 g os solution =

\frac{100 g}{125 g}*25 g

= 20 g

% m/m of solute = 20 % m/m

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25)

Evaluation

(1) - By the definition of Molarity the first statement is true.

[Molarity is the number of moles of solute dissolved in 1L of solution]

(2) - Volume of solution = volume of liquid solute + volume of liquid solvent . This statement is valid for Ideal solution only. Non-ideal solution in which association and dissociation phenomenon operate , do not agree with this statement. Because of repulsive forces between solute -solvent particles the volume changes . False

( 3) --Osmotic pressure is the is the pressure that need to be applied to a solution to halt the flow of solvent molecules through a semipermeable membrane or osmosis. ( in other words) This is definition of osmostic pressure. --- True

Result ------ Only statements 1 and 3 are right . Statement 2 is not correct.

Two of the state,ents are true.

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