q)
mass of solute = 25 g
mass of solvent = 100 g
mass of solution = 125 g
So 25 g of solute present in 125 g of solution.
% m/m of solute is determined by calculating mass of solute in 100 g of solution.
125 g of solution contains 25 g of solute.
100 g of solution contains how much solute = ?
So mass of solute in 100 g os solution =
= 20 g
% m/m of solute = 20 % m/m
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25)
Evaluation
(1) - By the definition of Molarity the first statement is true.
[Molarity is the number of moles of solute dissolved in 1L of solution]
(2) - Volume of solution = volume of liquid solute + volume of liquid solvent . This statement is valid for Ideal solution only. Non-ideal solution in which association and dissociation phenomenon operate , do not agree with this statement. Because of repulsive forces between solute -solvent particles the volume changes . False
( 3) --Osmotic pressure is the is the pressure that need to be applied to a solution to halt the flow of solvent molecules through a semipermeable membrane or osmosis. ( in other words) This is definition of osmostic pressure. --- True
Result ------ Only statements 1 and 3 are right . Statement 2 is not correct.
Two of the state,ents are true.
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