Here order is not matter so we can use combinations
there are total 10 students and we have to choose 5 students from total 10 students.
So there are 10C5 total ways of selcting committe of 5
= 10c5 = 10!/5!*5! = 10*9*8*7*6*5! /5*4*3*2*1 *5! = 30240/120 = 252
Also there are 4 boys in class of 10 and in commeittee of 5 we need 3 boys
So there are 4C3 total ways of selcting 3 boys in committe of 5
=4C3 = 4!/3!*1! = 4*3*2*1/3*2*1*1 =24/6= 4
Also there are 6 girls in class of 10 and in commeittee of 5 we need 2 girls
So there are 6C2 total ways of selcting 2 girls in committe of 5
=6C2 = 6!/2!*4! = 6*5*4*3*2*1/2*1*4*3*2*1 =720/48 = 15
So probability of selecting 3 boys and 2 girls is
4C3 * 6C2 / 10C5 = 4*15/ 252 = 60/252 = 5/21 = 0.2381
So the answer is 5/21
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