PLEASE ANSWER CLEARLY Suppose there are 30 students in a class of which 10 are boys...

Question

Question

PLEASE ANSWER CLEARLY

Answer 1

Answer #1

Solution:

Given

number of boys = 10

number of girls = 20

a) probability of selecting a boy out of 30 students is 10/30

probability of selecting a first girl out of 29 is 20/29

probability of selecting second girl out of 28 students is 19/28

therefore probability of selecting a boy first and then two girls is = (10/30)(20/29)(19/28) = 0.156

b) P(atleast one boy in 5 students) = 1 - P(no boy in 5 students)

= 1 - P( all 5 students are girls)

= 1 - 20C₅/30C₅

= 1 - 15504/142506

= 1 - 0.10879

= 0.891

Answer 2

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