When titrating 25.0 mL of 0.080 M HClO with 0.060 M NaOH, calculate the pH after adding 25.0mL of 0.050 M NaOH (pKa = 7.55).
A. 7.43
B. 7.55
C. 7.77
D. 10.08
E. 12.48
So the correct option is (C) 7.77
When titrating 25.0 mL of 0.080 M HClO with 0.060 M NaOH, calculate the pH after...
Question 16 10 points Save Answer Al titular 25.0 mL de HCIO 0.080 M con NaOH 0.060 M, calcule el pH después de haber añadido 25.0 mL de NaOH 0.050 M. (pka= 7.55) DA 7.43 B.7.55 0.7.77 D.10.08 E 12.48
When titrating 25.0mL of 0.080M HClO with 0.060M NaOH, calculate the pH after adding 25.0mL of 0.050M NaOH (pKa = 7.55).
When titrating 25.0mL of 0.080M HClO with 0.060M NaOH, calculate the pH after adding 25.0mL of 0.050M NaOH (pKa = 7.55).
1. Determine the Ka value for an acid that is 0.294 M in a solution that has a pH of 2.80. A 49 x 10-14 B. 23 x 109 C. 14 x 10-5 D. 20 x 10-5 OE 3.7x 10-7 2. When titrating 25.0 mL of 0.080 M HCIO with 0.060 M NaOH, calibrate the pH after adding 25.0 mL of 0.050 M NaOH (pKa = 7.55) A. 7.43 b.7.55 C.7.77 D.10.08 E 1248 3. The correct expression for the...
At 25.0 mL sample of 0.100 M HClO (aq) is titrated with NaOH (aq). What is the pH of the solution after the addition of 25.00 mL of 0.100 M NaOH? Ka of HClO=3.5*10^-8. The answer might be 4.70 but I don't know. Can anyone explain this problem to me? Full explanation please.
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