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Question 16 10 points Save Answer Al titular 25.0 mL de HCIO 0.080 M con NaOH...
When titrating 25.0 mL of 0.080 M HClO with 0.060 M NaOH, calculate the pH after adding 25.0mL of 0.050 M NaOH (pKa = 7.55). A. 7.43 B. 7.55 C. 7.77 D. 10.08 E. 12.48
1. Determine the Ka value for an acid that is 0.294 M in a solution that has a pH of 2.80. A 49 x 10-14 B. 23 x 109 C. 14 x 10-5 D. 20 x 10-5 OE 3.7x 10-7 2. When titrating 25.0 mL of 0.080 M HCIO with 0.060 M NaOH, calibrate the pH after adding 25.0 mL of 0.050 M NaOH (pKa = 7.55) A. 7.43 b.7.55 C.7.77 D.10.08 E 1248 3. The correct expression for the...
Question 1 20 points Save Answer You add 19.00 mL of 0.700 M NaOH to 50.00 mL of pure water, and to this mixture you then add 9.00 mL of 0.400 M HCL. What will be the pH of the resulting solution?
Question 2 20 points Save Answer You add 4.00 mL of 0.300 M NaOH to 50.00 mL of pure water, and to this mixture you then add 15.00 ml of 0.600 M HCI. What will be the pH of the resulting solution?
Question 5 20 points Save Answer You add 5.00 mL of 0.100 M NaOH to 75.00 mL of pure water, and to this mixture you then add 10.00 ml of 0.100 M HCI. What will be the pH of the resulting solution? Oo oo
Question 4 20 points Save Answer You add 10.00 mL of 0.200 M NaOH to 25.00 mL of pure water, and to this mixture you then add 5.00 ml of 0.100 M HCI. What will be the pH of the resulting solution? 7.00 OOOOO
20 points Save Answer You add 5.00 mL of 0.100 M NaOH to 75.00 mL of pure water, and to this mixture you then add 10.00 mL of 0.200 M HCI. What will be the pH of the resulting solution? 13.00 1.78 Support 12.22 1.00 7.00
Question 2 (10 points) If 25.0 mL of 0.451 M NaOH solution is titrated with 0.253 MH2SO4, the flask at the endpoint will contain (besides the indicator phenolphthalein) as the principal components: sodium hydroxide, sulfuric acid, and water dissolved sodium sulfate and water sodium hydroxide, sodium sulfate, and water dissolved sodium sulfate, sulfuric acid, and water precipitated sodium sulfate and water Question 3 (10 points) A 75.0-ml sample of 0.0650 MHCN (K-62 10-10) is titrated with 0.65 M NaOH. What...
(ueak acid/shing base 3. Calculate the pH at the following points for the titration of 25.0 mL of 0.100 M formic acid (Ka-1.80 x 10") with 0.100 M NaOH: VNOH 0.00 mL, 15.00 mL, 25.00 mL, 40.00 mL. Draw a graph of pH vs. VaoH. (30 points) (b) Buffer capacity can be thought of as how well a solution resists changes in pH after a strong base/acid is added. A buffer is most effective to resisting pH changes when what...
Question 3 20 points Save Ansy You add 5.00 mL of 0.100 M NaOH to 25.00 mL of pure water, and to this mixture you then add 10.00 mL of 0.200 M HCI. What will be the pH of the resulting solution? ooooo 1257 13.00