Question

Test 2 Question 11 of 15 (1 point) | Question Attempt 1 of 1 2 3 = 4 5 = 6 7 Let Z be a standard normal random variable. Calculate the following places. P(Z > 115) = 0 P(Z < 0.90) = 0 P(-0.56 << <212) = 0 Type here to search

Answer 1

We get Probability values of standard normal variable from statistical table.

1.

P(Z > 1.15) = 0.1251

2.

P(Z <=0.8) = 1 - P(Z > 0.8) = 1 - 0.2119 = 0.7881

3.

P(-0.56 < Z < 2.12)

= {P(Z < 2.12)} - P(Z < - 0.56)

= {1- P(Z > 2.12)} - P(Z > 0.56)

(P(Z < - 0.56) = P(Z > 0.56) since standard normal distribution is symmetric around zero)

= 1 - 0.017 - 0.2877

= 0.6953