Prove that f(x) = is uniformly continuous on (1,00) and not uniformly continuous on (0,1). (19...
9. Is the function f(x) = sin 1/x continuous on (0,1)? Is it uniformly con- tinuous on (0,1). Justify your answers. 10. Is the function f(x) = x sin 1/x uniformly continuous on (0, 1)? Justify your answer.
2. a. Prove that f(x) = V22 - 13 is uniformly continuous on the interval (7,0). b. Prove or disprove: f(x) = V x2 - 13 is not uniformly continuous on the interval ( 13, 7). c. Prove or disprove: If a > 13, f(x) = 32-13 is uniformly continuous on the interval (a,
3. Suppose that f [0,1(0,1) is a non-decreasing function (NOT assumed to be continuous). Prove or disprove that there exists x E (0,1) such that f(x)-x
Prove that f(x) is uniformly continuous on [0 inf) if lim f(x) = 0.
8. *** Prove that f(x) = ? is not uniformly continuous on (0,0). Remark: Recall that we proved in class that f(0) = .za is not uniformly continuous on (0,0). I remind you of this result in case it helps you think about how to approach this exercise.
Use the definition of uniform continuity to prove that f(x)is uniformly continuous on , 00
Suppose fon (0,1) is uniformly continuous. Show that there is a real number A such that the function F defined by F(O)=A, F(x)=f(x) if x € (0,1), is continuous on (0,1]. (Suggestion: Show first that if {Xn}, Xn € (0,1] has lim xn = 0, then {f(xn)} is a Cauchy no sequence. Then show this sequence has the same limit no matter which {Xn} sequence going to you choose).
10 marks) Prove that f(x) = 6 ln(x – 11) is not uniformly continuous on (0,0).
Let f: [0,1]→R be uniformly continuous, so that for every >0,
there exists δ >0 such that |x−y|< δ=⇒|f(x)−f(y)|< for
every x,y∈[0,1].The graph of f is the set G f={(x,f(x))
:x∈[0,1]}.Show that G f has measure
zero
Let f : [0, 1] → R be uniformly continuous, so that for every e > 0, there exists 8 >0 such that 2- y<83|f() - f(y)< € for every 1, 9 € [0,1]. The graph of f is the set Gj =...
Exercise 5. Prove that if f is a continuous and positive function on (0,1], there exists 8 >0 such that f(x) > 8 for any x € [0,1].