Question

Question 13:

How many milliliters of a 0.45 M solution contain 15.0 g of BaCl2? Express your answer using two significant figures

Question 14:

A bottle of 12.0 M hydrochloric acid has only 35.4 mL left in it.

A)What will the HCl concentration be if the solution is diluted to 270.0 mL ?

Answer 1

Auestion -13 ohn How many mililiters of a 0.45m solution contain 15gm of Bact2. Molecuta wright of Bully > 208.38 gm Ioel. So, Now we can find the number of moles of Ball, present in 15 gm of Bach,. 208. 38 gm Bally Imol Ball2 9m Ball, mol Ball 208.39 15 om Balla 15 208.38 mol Balla 2 0.07198 mol Bad, ne no. of moles of Ball 20.07198 mol ca concentration of the solution 2 0.45 M volume of the solution. nin 2 can Test (مساعد 06468 Va C 0.07199 0.45 2 0.1599 (L) 0.164) IL) 1000 TL 160 me. 1.0.16(L) (1000x 0.16) me So, 160 ml of a 0.45 m solution contain 15 gm of Bally solution.

Question 14 A bottle of 12.0 M Hel has only 35.4 me left in it what will be the concentration abe if the solution diluted to 270 ml? An At first concentration of Hella 12.01 ze, rolume Hel 2 35.4 ml z vi A Then, 2 270ml=V. volume of tee (dilection) concentration of tee ? nee know theet. en 2CV, =C2 12.0M X 35.4 me 2 C₂ X 270 ml C ez 12:04 x 3.5 4 mnd 270 me Z 1.57 33 M So, the concentration will be 1.5733M if the solution is diluted to 270 ml.