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The coach of the Dracut Marmosets, another soccer team, wants to determine if a stretching routine leads to a greater kicking

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Answer #1

1)

Let x_1 be Before stretching and 12 be After stretching.

Here we have to test that

Null hypothesis: H_0:\mu_d=0

Alternative hypothesis: 0 > Prl: H

where \mu_d=\mu_1-\mu_2

2)

Paired t test

3)

Sample mean for difference (d):

\bar{d}=\frac{\sum d}{n}=\frac{46}{6}=7.67 (Round to 2 decimal)

x_1 12 d_i=x_2-x_1

(d_i-\bar{d})^2

=(d_i-7.67)^2

74 83 9 1.769
47 54 7 0.449
73 75 2 32.149
68 72 4 13.469
70 82 12 18.749
57 69 12 18.749
\sum d=46 \sum (d_i-\bar{d})^2=85.333

Sample standard deviation for difference (d) :

s_d=\sqrt{\frac{\sum (d_i-\bar{d})^2}{n-1}}

s_d=\sqrt{\frac{85.333}{6-1}}

s_d=\sqrt{\frac{85.333}{5}}

s_d=\sqrt{17.06668}

s_d=4.131 (Round to 3 decimal)

Test statistic:

t=\frac{\bar{d}-\mu_d}{s_d/\sqrt{n}}

t=\frac{4.67-0}{4.131/\sqrt{6}}

t=\frac{4.67}{1.686474}

t = 2.769 (Round to 3 decimal)

Test is left tailed test.

Degrees of freedom = n - 1 = 6 - 1 = 5

Level of significance = \alpha = 0.05

P value from excel using function:

=T.DIST.(2.769,5,TRUE)

=0.9803 (Round to 4 decimal)

P value = 0.9803

4)
Here p value > \alpha

So we reject H0.

5)
Conclusion: There is sufficient evidence to determine that the stretching routine leads a greater kicking performance for her team.

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