Question

12 Ο Α Α Aa A 2 AaBbccdee AaBbcode Eu ES DE AaBbCcDc AaBb CcDdE X x A DAY Normal No Spacing Heading 1 Heading 2 One of the following tables describes the probability distribution of a discrete random variable X. For the one that does not give a reason why. For the one that does, compute the expected value u = E(X) (hint: answer is an integer). х -1 0 P(x) 0.2 0.2 0.6 XP(x) 1 0.3 2 0.5 3 0.3 2

Answer 1

We know that,

For being probability distribution, The sum of all probabilities should be 1 and each probability should be positive.

Now,

For first table, All probabilities are positive with sum 1.

Hence, It is probability distribution.

So, Mean= 1

And

For second table(Right hand side)

The sum of probability is, 0.3+0.5+0.3= 1.1, which is not equal to 1.

Hence, It is not probability distribution.

Thank you.

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