Question

Consider the following hypotheses: H0 M = 130 HA A 130 The population is normally distributed with a population standard deviation of 56. (You may find it useful to reference the appropriate table: z table or table) a-1. Calculate the value of the test statistic with 7 = 149 and n= 45. (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic a-2. What is the conclusion at the 5% significance level? O Do not reject Hosince the p-value is greater than the significance level. Do not reject Ho since the p-value is less than the significance levell O Reject Ho since the p-value is greater than the significance level. O Reject Ho since the p-value is less than the significance level.

Answer 1

Solution Gwen data, Hoi 4 =130 НА : M +130 =56 9-1 ve = 149 n = 45 Test statistics 1 149 - 130 z = X-4. olin = 2.27599 S 2,276 196/145 Test statistie = 2.276 9-2 P-value = 2x [P (23, 2.276)] = 240.0114 P-value 0.0228, (PCQ=0.05) Reject Ho Comeet option sy ② Reject Ho since since the p-value is less than the significance level. 9-3 we conclude that the population mean difters from 130, b-1 Given, h = 115 n = 45 še 115 - 130 -7.79685-1-80 test statistics & Z- olin 56/d45

Test statistic = -1,80 (6.2 p-value = 2xP(Z <1.00) = 9x0.0359 P-value = 0.0719 (P-value >=0.01) fail do Reject to Coreet option M B Do not reject Ho, since the p-value is greater than the Significance level 3. Correct А option M we cannot conclude that the population mean differs from 130,