The solution of the Initial-Value Problem (IVP) (x + y)dx - xdy = 0 ((1) =...
Question 1 3 pts The solution of the Initial-Value Problem (IVP) Į (x + y)dx – xdy = 0 1 y(1) = 0 is given by Oy= (x + y) In x None of them Oy= xel-1-1 O y = x ln(x + y) Oy= x In x
Question 1 3 pts The solution of the Initial-Value Problem (IVP) S (x + y)dx – «dy = 0 is given by 1 y(1) = 0 Oy=det-1 - 1 Oy= < ln(x + y) Oy= (x + y) In x Oy= < In x None of them Question 2 3 pts The general solution of the first order non-homogeneous linear differential equation with variable coefficients dy (x + 1) + xy = e-">-1 equals dx 2 Oy=e* (C(x - 1)...
The solution of the Initial-Value Problem (IVP) ((2 + y)dz - edy=0 (1) = 0 is given by Oy=ze?-1-1 O = em ? None of them Oy= (x + y) lns Oy= 2ln(0+ y)
Зрт Question 1 f (x + y)da - ady=0 The solution of the Initial-Value Problem (IVP) 1 y(1) = 0 is given by Oy= (x + y) In a Oy = x In a Oy= « ln(x + y) 3 = teº-1 None of them n Question 2 3 pts The general solution of the first order non-homogeneous linear differential equation with variable dy coefficients (a +1) + xy = e > -1 equals da 3 Oy= e-* [C(x2 -...
The solution of the Initial-Value Problem (IVP) ( z* yn – 2y = 4(x - 2) y(1) = 4 Y (1) = -1 is None of them 1 yang +82-2+3 1 y = +23 - 2x + 4 Oy - 1/4 +2² - 22+4 4 y= + x2 – 22+1
1. Find the solution to the IVP : yy - x = 1, y (0) = 2 2. Find the general solution to the exact DE: e* dx – ydy = 0 3. Use ji = cos y to find an EXPLICIT solution to: (tan y)dx + xdy = 0
The solution of the Initial-Value Problem (IVP) z? yll – 2y = 4(x - 2) y(1) = 4 y (1) = -1 is . 4 y == + x2 - 2x + 1 2 None of them 0 1 O y = +22 - 2x + 4 2 O y = 1 +73 - 2x + 4 22 O v= +222+3
Question 7 3 pts The solution of the Initial-Value Problem (IVP) zy! - 2y = 4(x - 2) y(1) = 4 y (1) = -1 is 1 23 +22 -3 +3 +2.3 -2.0.4 1 Y L 22 - 2.0 + 4 2 None of them 0 4 2.- - 2 + 1 y = 2 Question 8 3 pts The power series solution of the Initial-Value Problem (IVP) (22 +1)yll + xy + 2xy = 0 y(0) = 2 is...
The power series solution of the Initial-Value Problem (IVP) (x² + 1)yl + xy + 2xy = 0 y(0) = 2 is given by y(0) = 3 4 13 325 2 y=2(1 + + :). 2 + + 3 20 6 2 2125 y= 2 + 3x + +. 6 2 4 23 3.25 y = 32 =3(< + + -) +2 (1 + + :) 3 20 6 2 7.23 21.25 y= 2 + x + + + +......
The power series solution of the Initial-Value Problem (IVP) (x² + 1)yl + xy + 2xy = 0 y(0) = 2 is given by y(0) = 3 4 13 325 2 y=2(1 + + :). 2 + + 3 20 6 2 2125 y= 2 + 3x + +. 6 2 4 23 3.25 y = 32 =3(< + + -) +2 (1 + + :) 3 20 6 2 7.23 21.25 y= 2 + x + + + +......