Question

7. The rod CD is rotating with an angular velocity OCD = 2 rad/s. Determine: i) The velocity of point C and show its direction in the figure below ii) What is the angular velocity of link BC? 111) What is the velocity of points B and E? iv) What is the angular velocity of link AB? (30 points) 0.2 m 0.2 m B E 0.4 m 30° WCD= 2 rad/s D

Answer 1

i) ve (WD) Coco (2)(0.4) 909 IV Web 2 0.8 m/s ve is -oog i ii) Angules velocity of link BC= ? šar: 0.41 vecter of C worit Bi position cocentes clockwise Links BC and AB roketing -> WBC= wo E AB = WAB ВС VB= (AB) (WAB) 68 0.4m from giuon geometry WDB 0.4 sin30 = 738 AB CA >) AB = 0.8 m 0-8 WAB VB VB costo it VB 8inboj VB 0-8 WAB singoj -0-8 WAB Cosoo it VB - Orly WAB " +0.693 WAB I

Wer = EN btw Bt BC Ansus for post iu WAB 0-693 WAB to.4 C and Bi Relative velocity w x8cIB ) cross product -0.8i = (-0.4 Cari +0.693 WAB j J + (Work X0.4%) -0.81 (-0.4 WoBit 0.693 WA BJ) + (0.4 WBC j) [.kx;=j] -oofi = i (-0.4 WAB) + j (0-693 WAB to.4W Br.) both sides Equating components on -0.4 WAB -0.8 ССС) both sides Equating j Components on Oo69302 > WBC 0.4 aradis L WBC radis ССЫ 3.464 gadis CW WBC =7 3.964

(WAB) CAB) (2) (0.8) VB 16 mis &81E=0.21 Poistion of wrt ja Je SCIE WBC X -o si = E + (-3.464 EX 0.2;) - o.fi ve -0.6930 =) JE -oosit 0.693 j IVE) v (0.8) 2+ Co-69372 VG 1.06 ms Ccw. WAB zradis