Question

7. The rod CD is rotating with an angular velocity cp = 2 rad/s. Determine: i) The velocity of point and show its direction in the figure below ii) What is the angular velocity of link BC? iii)What is the velocity of points B and E? iv) What is the angular velocity of link AB? (30 points) 0.2 m 0.2 m B E 0.4 m 30° WcD= 2 rad/s D

Answer 1

steps:-

1. At first we make configuration diagram which is given in question

2. After it we calculate some geometrical calculation like length of link AB.

3. Now we construct kinetic diagram of each link with correct direction of velocity.

4. Now we calculate the velocity of of unknown which is ask in question during solution we apply a most important concept of rigid body which is along a line linear velocity is always constant.

concept:-

by Geometry. Absinzo = CD= .4m AB= sum sinzo AB=.8m с 2/rad/oum 3 WCDC kinematic Diagrom WBX AB B WCDX CD oc 60° WCDX CDI WABX : link(CD) e lup B = 2 Vc = "(DY CD VB= 16M WAB VB AB Sy. VE=? 1-6 .8m Worex:27 Vc direction () Vr =.8m WAB = 2rad zradu (Anticloa wise) Worx 12 = .6928 m BC is Rigid unk. and velocity along Bl must be some for condition of Rigid body VE = VE = 1.0583 Vc = WCDXC D =VB (0560 .8=VB (0560 VB = 1:6 M WBC = VBly sinto BC 1.6 x sinto .4 202077/31 22:12 = way 3.464 vol Seone

by using geometry and simple mechanics we find unknown.