Question

7. The rod CD is rotating with an angular velocity OcD = 2 rad/s. Determine: i) The velocity of point C and show its direction in the figure below ii) What is the angular velocity of link BC? iii)What is the velocity of points B and E? iv)What is the angular velocity of link AB? (30 points) 0.2 m, 0.2 m B E 0.4 m WCD= 2 rad/s 30°

Answer 1

Given: قيا = aradla CD 7 CD 0.4m Bc 0.4 m of AB To find the length ABF consida triangle B 0.4 c. BE - AB sin 30° 004 1.0.4 AB sin 30 0.4 130° D A B = Sin 30 F A AB = 0.8m CD consider link CDX LOCO Vc с Velocity at point ca Ve 0.4* Q Ve = '0.8 m/A zrade. fa Velocity d'agrams for the mechanians bo ☆ a 0-8 d

from the triangle abe ab costo р. 8 х сол бо" - - о. 8 о. 8x DAg + сол во (UAB (ABх села ) ов & radla from triangle abc ab sin 66 cb (ABx tap ) (sm6o) (о. 8x 2 ) ( sin bo) - 0-4 x Use 3- +64) та | ВСх9. Вс .. Вс. I-centers fox the Mechanism (9ge T3 1 Tзч, 50° 13 B E 12 @ 0 (Ф WAB зо" 9, A Точ 0 T,

from the triangle I, 9,34 I 23 13 (11g Isy) x ( COD 30°) - 1sy I 23 0.4 х con30" I 34 IB IB I34 0.4618 m I 13 I 34 x 9. BC B 11 at 2. Velocity point 0-4618 x 3.4641 1.6m/ from the triangle Io I23 I 23 E E I 13 (EI)" (123 Io)" (€ 1x3)*+ (Ig Izq Sin30)? (0.2) + (0.4618 * Singo)2 = 0.3054 m at velocity point Iiz Ex Woc = 0. 3054 x 204 3.4641 1.0579 MIA
Velocity of point C = 0.8 m/s ( towards right)

Angular velocity of link BC = 3.4641 rad/s

Velocity of point B = 1.6 m/s

Velocity of point E = 1.0579 m/s

Angular velocity of link AB = 2 rad/s