Question

9. (10 points) An orifice meter with a 1.0 inch diameter opening is used to measure the flow rate of water through a horizontal 3 inch diameter pipe. A mercury manometer is used to measure the pressure difference across the orifice. If the differential height of the manometer is 30 inches, determine the volumetric flowrate (gal/min) of water through the pipe. You may assume the discharge coefficient is 0.6.

Answer 1

So volumetric flow rate through pipe is 15.578 gal/min. calculation is done with the help of calculator. here we also use unit conversion.

9. sol. – given data are- orifice diameter (da)= 1 inch We 4 4 whene horizontay pire diacape sinen differential height of the manometer (h) = soinches discharge coefficiente col = 0.6 know the formula for calculating volumetric flow rate 9 = co Ao Ap / 29 Ah Ah - 30 inches VARAO Ap= II dp² = I x 3 = 7.068 inch Aon Area of orifice A = I do = I x 12 = 0.785 imena Ap = Area of pipe go gravity, ( 386.08 ineri/s) - volumetric flow rate to = diskhenge ceefficient on = differential weight Q = 0.68 0.7858 7.068 2x386X30 – 7.0688.7852 72.124 inch X han 3 a sec Now we know I cubic inch linen = 0.0036 gal and I min u Gosec a- 72.124 inch? to see x 0.0036 gal linen Фа sel imin 15.578 gal/min so, volumetric flow rate of water through pire is a = 15.578 gallmin

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