Problem 1: Given the RLC circuit with current source as shown (assume the system is initially...
A phasor diagram is drawn for a series RLC circuit driven by a source of alternating (sinusoidal) voltage. Four phasors are drawn: VL, I, Vc, and VR at a particular instant in time. The frequency of the voltage source (i.e. the signal generator) is set to a value larger than the resonant frequency of the circuit. a. Label each phasor appropriately and identify the angle indicated by the arc with its appropriate label. b. Draw a fifth phasor on the...
5) For the RLC circuit, assume that the capacitor is initially charged and after the switch is closed, show that the differential equation for the current is: d1 Rd 1 dt Ld LC (Hint: Start by writing voltages for each component VR, VL & Vc, and add them to zero (using Kirchhoff's voltage rule) then differentiate).
2-a)-RLC components connected in series in a circuit supplied by a variable dc voltage can be described by the following differential equations: di(t) wherei@ is the loop current and V1(t) İs the voltage drop across the inductor.+' The voltage drop across the resistor is given by Ohm's law vR(t) R i(t) and the voltage drop across the capacitor vc(t) is given by i(t) dt For a series circuit ye)t vit)t velt) v(t) where v(t) is applied voltage: Figure 3: RLC...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 190 V, and the frequency is f = -0 Hz. Given that L = 0.6 H, C = 75 uF, and VR = 20 V, find: a) I (rms); I = b) R; R= c) VL (rms); VL = d) Vc (rms). Vc =
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V f = 260 Hz. Given that L -0.35 H, C = 454F, and Vr = 75 V.find: 220 V, and the frequency is a) I (rms) I = 0.6452 A b) R R 116.2 12 c) VL (rms); VL 116.48 V d) Vc (rms). 27.35 Vc V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 150 V, and the frequency is f 240 Hz. Given that L = 0.1 H, C = 40 uF, and VR = 20 V, find: T a) I (rms); I A b) R; R 12 c) VL (rms); VL: V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 220 V, and the frequency is f = Hz. Given that L 0.35H, C = 45 pF, and VR = 75 V. find: 260 2 a) I (rms); A b) R; R 22 c) VL (rms); VL V d) Vc (rms). Vc V
Consider the simple series RLC circuit shown in figure below, the circuit has the following parameters, R=12, L = 0.2 Henry, and C = 0.05 Farad, R 1000 Vs The system is governed by the following equations: V = VR + V + V VR = IR V = Vc S(t)dt Or I = CM Construct a Simulink model for this system such that the input is the supply voltage Vs and the output is the voltage across the resistor...
(0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 200 V, and the frequency is f 290 Hz. Given that L = 0.25 H, C = 60 uF, and VR = 65 V, find: = 7T a) I (rms); I = A b) R; R= 12 c) VL (rms); Vi V d) Vc (rms). Vc = V
290 Hz. Given that (0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 170 V, and the frequency is f L 0.2 H, C 30 uF, and VR = 20 V, find: a) I (rms); I A b) R; R= 12 c) VL (rms); VL = V d) Vc (rms). Vc = V