To find the solution of the Initial-Value Problem \(\left\{\begin{array}{l}y \prime \prime-4 y=16 \cos 2 t \\ y(0)=0 \\ y^{\prime}(0)=0\end{array}\right.\) the
Laplace Transform was applied and it was obtained as "Laplace Transform" of the unknown function \(y=f(t)\), the following:
\(L\{f(t)\}=\frac{1}{s-2}-\frac{s}{s+2}-\frac{2 s}{s^{2}+4}\)
None of them
\(L\{f(t)\}=\frac{2 s}{s-2}-\frac{1}{s+2}-\frac{s}{s^{2}+4}\)
\(L\{f(t)\}=\frac{1}{s-2}+\frac{1}{s+2}-\frac{2 s}{s^{2}+4}\)
\(L\{f(t)\}=\frac{2}{s-1}+\frac{1}{s+4}-\frac{2 s}{s^{2}+4}\)
Use the Laplace transform to solve the given initial-value problem.$$ y^{\prime}+y=f(t), \quad y(0)=0, \text { where } f(t)=\left\{\begin{array}{rr} 0, & 0 \leq t<1 \\ 5, & t \geq 1 \end{array}\right. $$
Question 9 3 pts The Laplace transform of the piecewise continuous function J4, 0< < 3 f(t) is given by 2, t> 3 2 L{f} (2 - e-st), 8 >0. S L{f} (1 – 3e-), 8>0. 8 2 L{f} (3 - e-s), 8 >0. S L{f} = (1 – 2e-st), s > 0. None of them Question 10 3 pts yll - 4y = 16 cos 2t To find the solution of the Initial-Value Problem y(0) = 0 the y...
The objective of this question is to find the solution of the following initial-value problem using the Laplace transform. The objective of this question is to find the solution of the following initial-value problem using the Laplace transform y"ye2 y(0) 0 y'(0)=0 [You need to use the Laplace and the inverse Laplace transform to solve this problem. No credit will be granted for using any other technique]. Part a) (10 points) Let Y(s) = L{y(t)}, find an expression for Y(s)...
Consider the following initial value problem, representing the response of an undamped oscillator subject to the ramp loading applied force g(t): 0<t<2, y' + 25y = g(t), y(0) = 0, y(0) = -2, g(t) = 2<t<6, otherwise. 0 t - 2 2 2 In the following parts, use h(t – c) for the Heaviside function he(t) when necessary. a. First, compute the Laplace transform of g(t). L{f(t)}(s) b. Next, take the Laplace transform of the left-hand-side of the differential equation,...
Find the Laplace transform Y(s) = L{y} of the solution of the given initial value problem: 1, y' + 9 = 0<t<T 0,7 <t< y(0) = 5, y'(0) = 4
Consider the following initial value problem, representing the response of a damped oscillator subject to the discontinuous applied force f(t): y" +2y +10y = f(t), y(0) = 6, 7(0) = -3, f(t) = (1 3<t<4, 10 otherwise. {o In the following parts, use h(t -c) for the Heaviside function he(t) when necessary. a. First, compute the Laplace transform of f(t). L{f(t)}(s) = b. Next, take the Laplace transform of the left-hand-side of the differential equation, set it equal to your...
Part B (5 points each] An initial value problem y' + 2y = f(©),y(0) = 0 is to be solved by Laplace transforms. (B-1) When f(t) is depicted in the following, show that its Laplace transform can be obtained as f(t) 4 4e F(s) = [[f(t)) = 5ż (1-es). 4 -S s V 2 0 1 2: (B-2) Show that the Laplace transform of the solution, Y(s) = Ly(0)], can be obtained as 4 4(+ 1) Y(s) = s-(s +...
Question (2): Laplace Transformsa) Find the Laplace Transform of the following using the Laplace Transform table provided in the back:$$ f(t)=\frac{1}{4}\left(3 e^{-2 t}-8 e^{-4 t}+9 e^{-6 t}\right) u(t) $$b) Find the inverse Laplace Transform \(F(s)\) of the following function \(f(t)\) using the table:$$ f(t)=\frac{12 s^{2}(s+1)}{\left(8 s^{2}+5 s+800\right)(s+5)^{2}(10 s+8)} $$
I have the first method complete, but I can't figure out the second method Could someone please show how to use the second method?2. Find the unit step response of:$$ \begin{aligned} \dot{\overrightarrow{\mathbf{x}}}(t) &=\left[\begin{array}{cc} 0 & 1 \\ -2 & -2 \end{array}\right] \overrightarrow{\mathbf{x}}(t)+\left[\begin{array}{l} 1 \\ 1 \end{array}\right] u(t) \\ y(t) &=\left[\begin{array}{cc} 2 & 3 \end{array}\right] \overrightarrow{\mathbf{x}}(t) \end{aligned} $$by two methods (1): transfer function and then (2) \(y(t)=\mathbf{C} e^{\mathbf{A} t} \overrightarrow{\mathbf{x}}(0)+\mathbf{C} \int_{0}^{t} e^{\mathbf{A}(t-\tau)} \mathbf{B} u(\tau) d \tau+\mathbf{D} u(t)\). Re-member that the Laplace...
In this exercise we will use the Laplace transform to solve the following initial value problem: y"-2y'+ 17y-17, y(0)=0, y'(0)=1 (1) First, using Y for the Laplace transform of y(t), i.e., Y =L(y(t)), find the equation obtained by taking the Laplace transform of the initial value problem (2) Next solve for Y= (3) Finally apply the inverse Laplace transform to find y(t)