#3.
% m/v solution = (mass of solute/volume of solution)×100 .
10% m/v solution of glucose means , 10g glucose is present in 100mL of solution.
Then for 100g glucose, solution required is ;
(100mL solution/10g glucose) × 100g glucose = 1000mL of the solution is required.
Thus we require 1000mL of glucose solution for 100g of glucose.
#4. 0.5% m/v means , 0.5g of KCl is present in 100mL of solution.
For 20mL solution , we need KCl ;
(0.5g KCl/100mL solution) × 20mL solution = 0.1g of KCl is required.
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