Question

questions 1-5

QUESTION 1 How many milliliters of an 80% (V/V) solution of isopropyl alcohol would you need to make 355 mL of a 47.1% (v/v) solution of isopropyl alchohol? QUESTION 2 The ratio of solute to solvent expressed in some set of units is the QUESTION 3 For very dilute solution we sometimes use parts per million, also known as QUESTION 4 How many grams of NaOH would be needed to make 773 mL of a 2.76 M solution? QUESTION 5 How many moles of sodium chloride are in 751 mL of a 2.14 M solution of sodium chloride?

Answer 1

kindly post different questions separately. please rate

Questions MINI - M2 V2 Dilution Rule Mi and I are initial concentration and volume of isopropyl alcohol solution respectively. Ma and I are final concentration and volume of isopropyl alcohol soletion respectively Mi = 80 40 Ma = 47.1.06. Vi= ? 1/2 = 355 ML VI = Mala = 47.17 X 355mL = 209 mL 80% Hence, 209 mL of 801. (Hrv) solution of isopropyl alcohol will be needed.