Question

use newtons 2nd law to determine to determine distance travled by the block at t=3 s, starting from rest. assume block over comes static friction at t=0. F(t) applied horzontal direction

F(*): 10 + LJE N, tisin seconds FLA) horizontal =.2

Answer 1

AN a normal force F(t) f fra MK N mg Imet: flt): 10+2 Vt Newton Net horizontal orizontal fore feet Ft) - from fr - MAN - Miking : 0.2% 4x9.81 ***** . Imeta 2 10+2 vt 0.2% 4 x 9.81 fnet a 2:152 + 2 vt Newtons

According to Newton's 2nd law.. Fama 2.152 +2rt Ча s ao 0.538 +0.5 VE dut We know that a= dv & vada dt where as acceleration, to velocity, da displacement. a= dy 38 0.538+ 0.5VE at 7 dva (0.53 +0.5 VE) dt Integrating Vs 0.5388 t 0.5 t 115 at t=0, v=0 3/2 + с .'. 0 2 0 toto C=0

312 : Vo 0.538 + 3 3/2 : Vida 0.538t t wolt at 3 312 2 t 3 I dt a) daz (0.53 38tt Again integrating : 5/2 22 0.538t? + 3x8 a> 0.269 +2+ 2 t t + C₂ 2 512 of C2 15 at t=0, x 20 02 0 + 0 + C2 => C220 + .. x 0.269+? 2 7572 15 when t= 35. X: 0 269x32+ 2 x 3 15 a= 4.5m 5/2 = 4.4995mn 4.5m